28(t)=16t^2

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Solution for 28(t)=16t^2 equation:


Simplifying
28(t) = 16t2

Solving
28t = 16t2

Solving for variable 't'.

Combine like terms: 16t2 + -16t2 = 0
28t + -16t2 = 0

Factor out the Greatest Common Factor (GCF), '4t'.
4t(7 + -4t) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 't' equal to zero and attempt to solve: Simplifying t = 0 Solving t = 0 Move all terms containing t to the left, all other terms to the right. Simplifying t = 0

Subproblem 2

Set the factor '(7 + -4t)' equal to zero and attempt to solve: Simplifying 7 + -4t = 0 Solving 7 + -4t = 0 Move all terms containing t to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -4t = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -4t = 0 + -7 -4t = 0 + -7 Combine like terms: 0 + -7 = -7 -4t = -7 Divide each side by '-4'. t = 1.75 Simplifying t = 1.75

Solution

t = {0, 1.75}

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